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Diffstat (limited to 'fs/btrfs/inode.c')
-rw-r--r--fs/btrfs/inode.c112
1 files changed, 84 insertions, 28 deletions
diff --git a/fs/btrfs/inode.c b/fs/btrfs/inode.c
index da828cf5e8f8..d2e732d7af52 100644
--- a/fs/btrfs/inode.c
+++ b/fs/btrfs/inode.c
@@ -108,6 +108,13 @@ static struct extent_map *create_pinned_em(struct inode *inode, u64 start,
static int btrfs_dirty_inode(struct inode *inode);
+#ifdef CONFIG_BTRFS_FS_RUN_SANITY_TESTS
+void btrfs_test_inode_set_ops(struct inode *inode)
+{
+ BTRFS_I(inode)->io_tree.ops = &btrfs_extent_io_ops;
+}
+#endif
+
static int btrfs_init_inode_security(struct btrfs_trans_handle *trans,
struct inode *inode, struct inode *dir,
const struct qstr *qstr)
@@ -1542,30 +1549,17 @@ static void btrfs_split_extent_hook(struct inode *inode,
u64 new_size;
/*
- * We need the largest size of the remaining extent to see if we
- * need to add a new outstanding extent. Think of the following
- * case
- *
- * [MEAX_EXTENT_SIZEx2 - 4k][4k]
- *
- * The new_size would just be 4k and we'd think we had enough
- * outstanding extents for this if we only took one side of the
- * split, same goes for the other direction. We need to see if
- * the larger size still is the same amount of extents as the
- * original size, because if it is we need to add a new
- * outstanding extent. But if we split up and the larger size
- * is less than the original then we are good to go since we've
- * already accounted for the extra extent in our original
- * accounting.
+ * See the explanation in btrfs_merge_extent_hook, the same
+ * applies here, just in reverse.
*/
new_size = orig->end - split + 1;
- if ((split - orig->start) > new_size)
- new_size = split - orig->start;
-
- num_extents = div64_u64(size + BTRFS_MAX_EXTENT_SIZE - 1,
+ num_extents = div64_u64(new_size + BTRFS_MAX_EXTENT_SIZE - 1,
BTRFS_MAX_EXTENT_SIZE);
- if (div64_u64(new_size + BTRFS_MAX_EXTENT_SIZE - 1,
- BTRFS_MAX_EXTENT_SIZE) < num_extents)
+ new_size = split - orig->start;
+ num_extents += div64_u64(new_size + BTRFS_MAX_EXTENT_SIZE - 1,
+ BTRFS_MAX_EXTENT_SIZE);
+ if (div64_u64(size + BTRFS_MAX_EXTENT_SIZE - 1,
+ BTRFS_MAX_EXTENT_SIZE) >= num_extents)
return;
}
@@ -1591,8 +1585,10 @@ static void btrfs_merge_extent_hook(struct inode *inode,
if (!(other->state & EXTENT_DELALLOC))
return;
- old_size = other->end - other->start + 1;
- new_size = old_size + (new->end - new->start + 1);
+ if (new->start > other->start)
+ new_size = new->end - other->start + 1;
+ else
+ new_size = other->end - new->start + 1;
/* we're not bigger than the max, unreserve the space and go */
if (new_size <= BTRFS_MAX_EXTENT_SIZE) {
@@ -1603,13 +1599,32 @@ static void btrfs_merge_extent_hook(struct inode *inode,
}
/*
- * If we grew by another max_extent, just return, we want to keep that
- * reserved amount.
+ * We have to add up either side to figure out how many extents were
+ * accounted for before we merged into one big extent. If the number of
+ * extents we accounted for is <= the amount we need for the new range
+ * then we can return, otherwise drop. Think of it like this
+ *
+ * [ 4k][MAX_SIZE]
+ *
+ * So we've grown the extent by a MAX_SIZE extent, this would mean we
+ * need 2 outstanding extents, on one side we have 1 and the other side
+ * we have 1 so they are == and we can return. But in this case
+ *
+ * [MAX_SIZE+4k][MAX_SIZE+4k]
+ *
+ * Each range on their own accounts for 2 extents, but merged together
+ * they are only 3 extents worth of accounting, so we need to drop in
+ * this case.
*/
+ old_size = other->end - other->start + 1;
num_extents = div64_u64(old_size + BTRFS_MAX_EXTENT_SIZE - 1,
BTRFS_MAX_EXTENT_SIZE);
+ old_size = new->end - new->start + 1;
+ num_extents += div64_u64(old_size + BTRFS_MAX_EXTENT_SIZE - 1,
+ BTRFS_MAX_EXTENT_SIZE);
+
if (div64_u64(new_size + BTRFS_MAX_EXTENT_SIZE - 1,
- BTRFS_MAX_EXTENT_SIZE) > num_extents)
+ BTRFS_MAX_EXTENT_SIZE) >= num_extents)
return;
spin_lock(&BTRFS_I(inode)->lock);
@@ -1686,6 +1701,10 @@ static void btrfs_set_bit_hook(struct inode *inode,
spin_unlock(&BTRFS_I(inode)->lock);
}
+ /* For sanity tests */
+ if (btrfs_test_is_dummy_root(root))
+ return;
+
__percpu_counter_add(&root->fs_info->delalloc_bytes, len,
root->fs_info->delalloc_batch);
spin_lock(&BTRFS_I(inode)->lock);
@@ -1741,6 +1760,10 @@ static void btrfs_clear_bit_hook(struct inode *inode,
root != root->fs_info->tree_root)
btrfs_delalloc_release_metadata(inode, len);
+ /* For sanity tests. */
+ if (btrfs_test_is_dummy_root(root))
+ return;
+
if (root->root_key.objectid != BTRFS_DATA_RELOC_TREE_OBJECTID
&& do_list && !(state->state & EXTENT_NORESERVE))
btrfs_free_reserved_data_space(inode, len);
@@ -7213,7 +7236,7 @@ static int btrfs_get_blocks_direct(struct inode *inode, sector_t iblock,
u64 start = iblock << inode->i_blkbits;
u64 lockstart, lockend;
u64 len = bh_result->b_size;
- u64 orig_len = len;
+ u64 *outstanding_extents = NULL;
int unlock_bits = EXTENT_LOCKED;
int ret = 0;
@@ -7225,6 +7248,16 @@ static int btrfs_get_blocks_direct(struct inode *inode, sector_t iblock,
lockstart = start;
lockend = start + len - 1;
+ if (current->journal_info) {
+ /*
+ * Need to pull our outstanding extents and set journal_info to NULL so
+ * that anything that needs to check if there's a transction doesn't get
+ * confused.
+ */
+ outstanding_extents = current->journal_info;
+ current->journal_info = NULL;
+ }
+
/*
* If this errors out it's because we couldn't invalidate pagecache for
* this range and we need to fallback to buffered.
@@ -7348,11 +7381,20 @@ unlock:
if (start + len > i_size_read(inode))
i_size_write(inode, start + len);
- if (len < orig_len) {
+ /*
+ * If we have an outstanding_extents count still set then we're
+ * within our reservation, otherwise we need to adjust our inode
+ * counter appropriately.
+ */
+ if (*outstanding_extents) {
+ (*outstanding_extents)--;
+ } else {
spin_lock(&BTRFS_I(inode)->lock);
BTRFS_I(inode)->outstanding_extents++;
spin_unlock(&BTRFS_I(inode)->lock);
}
+
+ current->journal_info = outstanding_extents;
btrfs_free_reserved_data_space(inode, len);
}
@@ -7376,6 +7418,8 @@ unlock:
unlock_err:
clear_extent_bit(&BTRFS_I(inode)->io_tree, lockstart, lockend,
unlock_bits, 1, 0, &cached_state, GFP_NOFS);
+ if (outstanding_extents)
+ current->journal_info = outstanding_extents;
return ret;
}
@@ -8075,6 +8119,7 @@ static ssize_t btrfs_direct_IO(int rw, struct kiocb *iocb,
{
struct file *file = iocb->ki_filp;
struct inode *inode = file->f_mapping->host;
+ u64 outstanding_extents = 0;
size_t count = 0;
int flags = 0;
bool wakeup = true;
@@ -8112,6 +8157,16 @@ static ssize_t btrfs_direct_IO(int rw, struct kiocb *iocb,
ret = btrfs_delalloc_reserve_space(inode, count);
if (ret)
goto out;
+ outstanding_extents = div64_u64(count +
+ BTRFS_MAX_EXTENT_SIZE - 1,
+ BTRFS_MAX_EXTENT_SIZE);
+
+ /*
+ * We need to know how many extents we reserved so that we can
+ * do the accounting properly if we go over the number we
+ * originally calculated. Abuse current->journal_info for this.
+ */
+ current->journal_info = &outstanding_extents;
} else if (test_bit(BTRFS_INODE_READDIO_NEED_LOCK,
&BTRFS_I(inode)->runtime_flags)) {
inode_dio_done(inode);
@@ -8124,6 +8179,7 @@ static ssize_t btrfs_direct_IO(int rw, struct kiocb *iocb,
iter, offset, btrfs_get_blocks_direct, NULL,
btrfs_submit_direct, flags);
if (rw & WRITE) {
+ current->journal_info = NULL;
if (ret < 0 && ret != -EIOCBQUEUED)
btrfs_delalloc_release_space(inode, count);
else if (ret >= 0 && (size_t)ret < count)