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author | Gustavo A. R. Silva <gustavo@embeddedor.com> | 2019-06-06 13:18:53 -0500 |
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committer | Jessica Yu <jeyu@kernel.org> | 2019-06-07 10:56:32 +0200 |
commit | 8d1b73dd25ff92c3fa9807a20c22fa2b44c07336 (patch) | |
tree | 6212b290118a7f3c96aff18c0c1bac6da62b297f /tools/perf/scripts/python/export-to-postgresql.py | |
parent | 6e6de3dee51a439f76eb73c22ae2ffd2c9384712 (diff) |
kernel: module: Use struct_size() helper
One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct module_sect_attrs {
...
struct module_sect_attr attrs[0];
};
Make use of the struct_size() helper instead of an open-coded version
in order to avoid any potential type mistakes.
So, replace the following form:
sizeof(*sect_attrs) + nloaded * sizeof(sect_attrs->attrs[0]
with:
struct_size(sect_attrs, attrs, nloaded)
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: Jessica Yu <jeyu@kernel.org>
Diffstat (limited to 'tools/perf/scripts/python/export-to-postgresql.py')
0 files changed, 0 insertions, 0 deletions