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authorGustavo A. R. Silva <gustavo@embeddedor.com>2019-06-06 13:18:53 -0500
committerJessica Yu <jeyu@kernel.org>2019-06-07 10:56:32 +0200
commit8d1b73dd25ff92c3fa9807a20c22fa2b44c07336 (patch)
tree6212b290118a7f3c96aff18c0c1bac6da62b297f /tools/perf/scripts/python/export-to-postgresql.py
parent6e6de3dee51a439f76eb73c22ae2ffd2c9384712 (diff)
kernel: module: Use struct_size() helper
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct module_sect_attrs { ... struct module_sect_attr attrs[0]; }; Make use of the struct_size() helper instead of an open-coded version in order to avoid any potential type mistakes. So, replace the following form: sizeof(*sect_attrs) + nloaded * sizeof(sect_attrs->attrs[0] with: struct_size(sect_attrs, attrs, nloaded) This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: Jessica Yu <jeyu@kernel.org>
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